Election in Nebraska
1868 United States presidential election in Nebraska
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| | | Nominee | Ulysses S. Grant | Horatio Seymour | | Party | Republican | Democratic | Home state | Illinois | New York | Running mate | Schuyler Colfax | Francis Preston Blair, Jr. | Electoral vote | 3 | 0 | Popular vote | 9,772 | 5,519 | Percentage | 63.91% | 36.09% | |
Grant 50–60% 60–70% 70–80% 80–90% 90–100% | Seymour 50–60% 90–100% | |
President before election Andrew Johnson Democratic | Elected President Ulysses S. Grant Republican | |
Elections in Nebraska |
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The 1868 United States presidential election in Nebraska took place on November 3, 1868, as part of the 1868 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]
Nebraska participated in its first ever presidential election, having become the 37th state on March 1, 1867. The state was won by Ulysses S. Grant, formerly the 6th Commanding General of the United States Army (R-Illinois), running with Speaker of the House Schuyler Colfax, with 63.91% of the popular vote, against the 18th governor of New York, Horatio Seymour (D–New York), running with former Senator Francis Preston Blair, Jr., with 36.09% of the vote.[1]
Results
See also
References
- ^ a b c "1868 Presidential Election Results Nebraska".
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